delete a subplot and renew plot

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karlo gonzales
karlo gonzales 2014-6-16
评论： dpb 2014-6-17
Hi guys,
i am trying to update my subplot in a for loop, like;
fig1=figure;
for i=1:10
axes1 = axes('Parent',fig1, 'Position',[0.043 0.77 0.43 0.15]); box(axes1,'on'); hold(axes1,'all');
plot(rand(1,100),'Parent',axes1)
end
it works! and for each run i have a new graph. BUT, it has one problem; overlapping subplot box.
what should i do, to avoid this overlapping
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karlo gonzales
karlo gonzales 2014-6-17
Indeed, i don't have any more over-plotting box or axes with above-mentioned code
what i wanted to do was; open a figure+ several subplots at specific positions and update graphs in a for- loop.
dpb
dpb 2014-6-17
Actually, the one problem of multiple handles does go away with subplot for overlapping calls--it has the smarts internally to make the existing the current--but so does just the syntax
subplot(N,M,i)
It would still be much simpler to retain the handle that corresponds to each when creating them (or not save any handles at all) rather than have the same variable refer to a bunch of different axes depending...
As for updating once you've created an axes object, the use of set for [x|y]data is far more efficient as Kevin noted.

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回答（1 个）

Kevin Claytor
Kevin Claytor 2014-6-16
Better yet, update using handles:
figure;
f = 2*pi;
x = linspace(1,100);
y = sin(x/f);
subplot(2,2,1)
plot(x,y);
title('Initial')
subplot(2,2,4);
title('Over Time')
h = plot(x,y);
for ii = 1:1000
newy = sin(1/f*(x - ii/pi));
% update using the handle to the graphics object
set(h,'ydata',newy);
pause(.1)
end

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