Add up a certain number of consecutive values followed by the next values in a row

Question

Dennis Annutsch 2021-8-17

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https://ww2.mathworks.cn/matlabcentral/answers/1358507-add-up-a-certain-number-of-consecutive-values-followed-by-the-next-values-in-a-row

评论： Dennis Annutsch 2021-8-17

Good morning,

I am looking for a function that can do the following:

E.g.

A = [1 3 4 0 -1 6]

Result = 4 4 5

Always added up two values from the beginning - then the next two values - and so on.

It would be nice to have the option to say please always add up 3 values, so that the result would be: Result = 8 5

Thanks for your help!

Dennis

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Answer 1

Wan Ji 2021-8-17

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https://ww2.mathworks.cn/matlabcentral/answers/1358507-add-up-a-certain-number-of-consecutive-values-followed-by-the-next-values-in-a-row#answer_768527

在 MATLAB Online 中打开

I'll write for you!

function a = everynsum(arr, n)
p = length(arr);
a = sum(reshape(arr,n,p/n)); % in case mod(p,n)=0
end

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Wan Ji 2021-8-17

在 MATLAB Online 中打开

By movsum you can do:

A = [1 3 4 0 -1 6];
n = 2; % every 2 sum
B = movsum(A,n);
Result = B(n:n:end)

The result is

Result =
     4     4     5

Dennis Annutsch 2021-8-17

Thank you very much!! This works exactly as I imagined. I wish you all the best!

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Answer 2

Awais Saeed 2021-8-17

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1358507-add-up-a-certain-number-of-consecutive-values-followed-by-the-next-values-in-a-row#answer_768537

在 MATLAB Online 中打开

clc;clear all;close all
A = [1 3 4 0 -1 6];
n = 2;  % sum every n elements
jj = 0;
simdone = true; % to keep while loop running
while (simdone)
 jj = jj + 1;
 if (size(A,2) == n)
  result(jj) = sum(A(1:n));
  break % break while loop
 end
 result(jj) = sum(A(1:n));
 A(1:n) = [];   % deleting summed elements
end