Random split of a vector of unequal lengths

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Adib Zaman
Adib Zaman 2014-6-25
编辑： Image Analyst 2014-6-25
How can I split a vector in k unequal subsets? For example, if I have 200 data, a random split might give us 63, 95 and 150. That is 1:63, 64:95, 96:150 and 151:200.
Apology for cross postings.

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2014-6-25
k=4
v=1:200
m=numel(v);
idx=unique([randperm(m-2,k)+1 m]);
idx0=[1 idx(1:end-1)+1];
out=arrayfun(@(ii,jj) v(ii:jj),idx0,idx,'un',0);
celldisp(out)

更多回答（2 个）

Star Strider
Star Strider 2014-6-25
One way to do it:
A = 1:200;
ndiv = 3; % NUMBER OF SUBMATRICES
idx = sort([1 randperm(length(A)-2, ndiv-1)+1 length(A)+1])
for k1 = 1:length(idx)-1
R{k1} = A(idx(k1):idx(k1+1)-1);
end
The logic guarantees that every element of R has at least two elements. Choose the number of sub-matrices with ndiv.
John D'Errico
John D'Errico 2014-6-25
I don't see what is wrong with simply choosing k-1 values randomly between the min and max. Those points define a partition as you desire.
  1 个评论
Adib Zaman
Adib Zaman 2014-6-25
yes, the only problem is you need to sort it after the random number generation.

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