Fast creation of vector [0 0 1 1 2 2 3 3... n n]

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Simon
Simon 2014-6-30
评论： Paul Safier 2022-12-8
Hi all,
like mentioned in the title, is there a fast way of creating a vector with repeating digits?
Thanks!
Simon

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采纳的回答

per isakson
per isakson 2014-6-30
编辑：per isakson 2014-6-30
Test
>> reshape( cat( 1, [0:n], [0:n] ), 1, [] )
ans =
0 0 1 1 2 2 3 3 4 4 5 5
and
>> reshape( repmat( [0:n], 2,1 ), 1, [] )

更多回答（4 个）

Andrei Bobrov
Andrei Bobrov 2014-7-1
k = [1;1]*(0:n);
out = k(:)';
Jos (10584)
Jos (10584) 2014-6-30
n = 10 % max value
k = 3 % number of repetitions
V = floor((0:k*(n+1)-1)/k)
  3 个评论
显示 1更早的评论
Jos (10584)
Jos (10584) 2014-7-1
Reshaping does not take a lot of time. Is it also faster for larger values of k?
per isakson
per isakson 2014-7-1
编辑：per isakson 2014-7-3
Is this solution immune to floating point errors?

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Steven Lord
Steven Lord 2022-12-8
Ran in:
n = 5;
x1 = repelem(0:n, 2)
x1 = 1×12
0 0 1 1 2 2 3 3 4 4 5 5
Danilo NASCIMENTO
Danilo NASCIMENTO 2014-6-30
V=zeros(1,20);
k=0;
i=1;
while i<20
V(i)=k;
V(i+1)=k;
k=k+1;
i=i+2;
end
V

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