Generating random number between 1 to 10

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Aftab Ahmed Khan
Aftab Ahmed Khan 2014-7-1
评论： Souarv De 2021-10-8
Hi everyone,
I want to generate a random number between 1 to 10 for 10 loop iteration, with this code section of mine but i want that each time it generate a different number. Forexample if 2 is generated for the 1st loop iteration, then for the rest of 9 iteration. It won't generate 2 again. Similarly for the rest of other numbers between 1 to 10.
for i=1:10
r = (b-a)*rand(1) + a
end

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采纳的回答

dpb
dpb 2014-7-1
编辑：dpb 2014-7-1
That's "sampling w/o replacement". One relatively simple way--
N1=1; N2=10; % range desired
p=randperm(N1:N2);
for i=N1:N2
r=p(i);
...
ERRATA
As noted, in comment, forgot there isn't such a form for randperm. Seems like reasonable enhancement altho it's easy enough to scale externally, too.
Use
N=10; % range desired
p=randperm(N);
for i=1:N
instead.
  3 个评论
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dpb
dpb 2014-7-1
Ewww...mea culpa. I was thinking there was a vector version of inputs to randperm to move the range from the default 1:N to N1:N2 but there isn't. Was trying to generalize.
For your case, just use
N=10;
p=randperm(N);
for i=1:N
...
If you do need integers from other than 1:N, scale the resulting array as needed.

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更多回答（3 个）

Jos (10584)
Jos (10584) 2014-7-2
In matlab you can directly loop over a vector (no need for indexing)
V = randperm(10) % example vector
for x = V
% x will iterate over the values of V
disp(x)
end
Juan Gonzalez
Juan Gonzalez 2021-4-13
This is the easiest way
ceil(rand*10)
  1 个评论
dpb
dpb 2021-4-13
编辑：dpb 2021-4-13
But won't follow the request of OP to have sampling without replacement so that none can be repeated in the 10 samples.

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Elias Gule
Elias Gule 2014-7-2
N = 10; % size of the array
numArray = randperm(N); % array containing integers ranging from 1 : N
for k = numArray
%%perform some calculation/process
doSomething(k);
end

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