How can I find the largest number

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alessandro
alessandro 2014-7-2
回答： b.lokendra sri sai 2021-1-9
Hi, I have 3 numbers and I have to find the biggest one, what is the best way? This is the code:
T=200
if isempty(counter) || counter >= T
counter=0;
d1=0.1
d2=0.2
d3=0.6
else counter=counter+1
if counter>0
if d1=max([d1,d2,d3)]
...
elseif d2=max([d1,d2,d3)]
...
elseif d3=max([d1,d2,d3)]
...
end
end
end
But this code doesn't work, thank you
  3 个评论
显示 1更早的评论
alessandro
alessandro 2014-7-2
I just need to know which is the greater one in order to define another variable, for example:
if d1=max([d1,d2,d3)]
V=V1
elseif d2=max([d1,d2,d3)]
V=V1
elseif
...
Roberto Calandra
Roberto Calandra 2014-7-2
Remember that with d1=max([d1,d2,d3]) you are assigning a variable to d1but what you want is checking for equality as in d1==max([d1,d2,d3])

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采纳的回答

Elias Gule
Elias Gule 2014-7-2
numbers = [num1 num2 num3]; % the array of numbers from which to search
maxVal = max(numbers); % the highest number

更多回答（3 个）

Roberto Calandra
Roberto Calandra 2014-7-2
Something like this?
switch max([d1,d2,d3])
case {d1}
V=V1
case {d2}
V=V2
case {d3}
V=V3
end
Robert Cumming
Robert Cumming 2014-7-2
you need to use
==
for comparison, i.e.
if d1==max([d1,d2,d3)]
etc...
b.lokendra sri sai
T=200
if isempty(counter) || counter >= T
counter=0;
d1=0.1
d2=0.2
d3=0.6
else counter=counter+1
if counter>0
if d1=max([d1,d2,d3)]
...
elseif d2=max([d1,d2,d3)]
...
elseif d3=max([d1,d2,d3)]
...
end
end
end

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