expression substitution
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Hi, I would like to use regexprep to substitute a simple expression for another in a text.
As an example, I have the following expression A=g*ABC+(1-g)*(CAD+d*EEA)+ZI/A , and would like to replace all occurrences of the word A with A_subs. The result would be A_subs=g*ABC+(1-g)*(CAD+d*EEA)+ZI/A_subs . Could you suggest a simple call to regexprep that would do this? Thanks, Junior
回答（2 个）
David Young
2011-8-19
s = 'A=g*ABC+(1-g)*(CAD+d*EEA)+ZI/A';
regexprep(s, '(^|\W)A($|\W)', '$1A_subs$2')
EDIT: See Walter Roberson's comment for a more elegant solution.
4 个评论
Walter Roberson
2011-8-19
s = 'A=g*ABC+(1-g)*(CAD+d*EEA)+ZI/A';
regexprep(s, '(\<A\>)', '$1_subs')
Oleg Komarov
2011-8-19
@Walter: very elegant.
Andrei Bobrov
2011-8-20
Hi David, +1.
Hi Walter, super nice!
David Young
2011-8-20
Hi Andrei: thanks.
Hi Walter: wish I'd spotted that!
Andrei Bobrov
2011-8-19
char(subs('A = ABC*g + ZI/A - (CAD + EEA*d)*(g - 1)','A','A_subs'))
ADD MORE variant
str='A=g*ABC+(1-g)*(CAD+d*EEA)+ZI/A'
t = regexp(str,'A=|[*/-+=]+A+$|[*/-+=]+A+[*/-+=]')
str2 = mat2cell(str,1,[1 diff(t) 1])
str2(strcmp(str2,'A'))={'A_subs'}
strout = cell2mat(str2)
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