Hi every one briefly, I have i=3:5 and j=1:3 and My equation is how to let i=3 for calculating the first raw and let j changes from 1:3 and for second raw i =4 and let j changes from 1:3 and third raw i =4 and let j changes from 1:3 and third
% Calculate the first row.
i=3
for j=1:3
A(i,j)=(A(i-1,1)*A(i-2,j+1)-A(i-1,j+1)*A(i-2,1))/(A(i-1,1))
end
% Calculate the second row
i=4
for j=1:3
A(i,j)=(A(i-1,1)*A(i-2,j+1)-A(i-1,j+1)*A(i-2,1))/(A(i-1,1))
end
% Calculate the third row
i=5
for j=1:3
A(i,j)=(A(i-1,1)*A(i-2,j+1)-A(i-1,j+1)*A(i-2,1))/(A(i-1,1))
end

 采纳的回答

Try this:
clc; % Clear command window.
A = magic(5); % Create some sample data.
% Calculate the first row.
for row = 3 : 5
for column = 1 : 3
A(row, column)= ...
(A(row-1, 1) * A(row-2, column+1) - ...
A(row-1, column+1) * A(row-2, 1)) / ...
A(row-1, 1);
end
end
A % Print to command window.

2 个评论

Thank you very much Image Analyst
If you want to tall me what you want to do, there may be a vectorized way, or a function to do what you want to do.

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更多回答(1 个)

for i=3:5
for j=1:3
%calculations here.
end
end
Two suggestions: 1. Dont use i and j as variables in matlab as they denote sqrt(-1) 2. Pre allocate arrays before calculation for speed

1 个评论

thanks for replaying
it doesn't work, because I want i=3 for all the first row and j=1:3 and for the second row i = 4 and j=1:3 and so on

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