Simple Counter Problem using (i+1)

1 次查看(过去 30 天)
Hi Folks,
I have an excel 1 column 906 rows which i call into this script. I want to get the difference between the i+1 row and the ith row, ie B6-B5, B7-B6 all the way down the column. The problem is when i run into the last row i get the following error
"??? Attempted to access t(907); index out of bounds because numel(t)=906."
I suspect this is a classical problem with counters but i dont know a workaround. Thanks
Here is my script. The problem is the 2nd line "dt"
for i=1:906;
dt(i+1)=t(i+1)-t(i);
dT(i)=dt(i+1)*(P_loss(i)-h*As*(T_Oil(i)-T_amb(i)))/(ma*Cp);
T_final(i)=(T_Oil(i)+dT(i));
end

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2014-7-19
change your for loop
for i=1:906-1;

更多回答(1 个)

Jan
Jan 2014-7-19
Or more Matlabish without a loop:
dt = diff(t);
dT = dt .* (P_loss(1:905) - h*As*(T_Oil(1:905) - T_amb(1:905))) ./ (ma*Cp);
T_final = T_Oil(1:905) + dT;

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by