Odd output from ind2sub

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Kate
Kate 2014-7-23
评论： Kate 2014-7-23
I'm trying to spit out indices for max values in a large matrix at a specific point in time (in this case obs 1560, t(:, :, 1560))
>> [I J]=ind2sub(size(t), (max(max(t(:, :, 1560)))))
But my I is equal to the actual value in the cell, not the row
I =
28.5048
And J makes no sense:
J =
1
Is the error in my code obvious to anyone? Thanks,

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2014-7-23
编辑：Andrei Bobrov 2014-7-23
s = size(t);
[val,ij] = max(reshape(t(:, :, 1560),[],1);
[ii,jj] = ind2sub(s(1:2),ij);
idxs = [ii,jj,1560];
or
ind = prod(s(1:2))*1559 + ij;
  1 个评论
Kate
Kate 2014-7-23
Thanks Andrei, reshape was the addition that I needed.

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更多回答（1 个）

dpb
dpb 2014-7-23
(max(max(t(:, :, 1560))))
is a single value for the maximum of the values of the requested plane. Thus there isn't any actual location to be converted from being returned.
If you write
[i,j]=ind2sub(size(t), find(max(max(t(:, :, 1560)))))
instead, you'll always get [1,1] because the result of the double max() operation is scalar.

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