Info

此问题已关闭。 请重新打开它进行编辑或回答。

matrix shape is incorrect??

1 次查看（过去 30 天）
Kevin
Kevin 2014-7-24
关闭： MATLAB Answer Bot 2021-8-20
Hi, I have the following code which will give me values of F along a plane surface. It should give me a vecor matrix in a 1x9 shape. However the resulting matrix appears to be a 9x1 shape.
for Q=1:length(Phi)
if Phi(Q)<0;
F(Q)=1;
else
F(Q)=(2/pi) .* acos(exp(-(((B/2) .* (1-(r_over_R(Q)))) ./ ((r_over_R(Q)) .* sin(relative_wind(Q)))))); % Tip Loss Factor
end;
end;
Does anybody know how I can change this? Thanks.

此问题已关闭。

回答（2 个）

Wayne King
Wayne King 2014-7-24
编辑：Wayne King 2014-7-24
You don't give us all the variables here so we can't tell you how to change in the loop, but the simple thing to do is at the end of the loop (after the final "end"), just do
F = F';
The above assumes that F is real-valued. If F is complex-valued and you don't want to conjugate the elements, do
F = F.';
  1 个评论
Michael Haderlein
Michael Haderlein 2014-7-24
That's one option, or you just preallocate F by
F=zeros(size(Phi));
Then you'll get the same shape, improved memory efficiency and no more a warning at the respective line.
Best regards,
Michael
Azzi Abdelmalek
Azzi Abdelmalek 2014-7-24
It's simple, just transpose the result
A=A'

此问题已关闭。

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by