Complicated Question / String Arrays

Question

0 个投票

Hey Guys, i have an array of strings which looks like this:

'J_012(105)'    'J_013(106)'    'J_014(107)'    'J_015(2)'  J_016(94)'    'J_017(95)'

But I need it to look like this:

'J_012' 'J_013' 'J_014' 'J_015' 'J_016' 'J_017'

So That the ALWAYS the last 4Strings are deleted/kill. Is this possible ?

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Answer 1

dpb 2014-7-24

1 个投票

new= cellfun(@(x) x(1:5),old,'uniformoutput',false);

Max Müller 2014-7-24

Thanks..both ways wokr

dpb 2014-7-24

If the pattern isn't fixed length, then regexp is useful; if it is then it's overkill...good to see both

Answer 2

Azzi Abdelmalek 2014-7-24

0 个投票

A={'J_012(105)'    'J_013(106)'    'J_014(107)'    'J_015(2)'  'J_016(94)'    'J_017(95)'} 
B=cellfun(@(x) x{1} ,regexp(A,'.+(?=\()','match'),'un',0)

Max Müller 2014-7-24

Thanks..both ways work