How to extract points from a 3D plot that fall within a particular distance from the center coordinate?
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Hello, I am a novice in matlab programmming. I am working on a computational project where I have a 3dimensional plot with thousands of points. Now I would like to fix one point having coordinate (x,y,z). At a particular distance r as a cutoff from (x,y,z), I would like to extract all the points in the plot that fall within the distance (or radius) r. I am not sure of how i can use euclidean distance formula for this. Please help me out.
Thanks in advance.
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Wan Ji
2021-8-18
编辑:Wan Ji
2021-8-18
If you have Coor is a n by 3 matrix as the coordinates of n points in 3d space and a fixed point (x,y,z). Then the points within the distance r can be obtained by
p = sqrt((Coor(:,1)-x).^2 + (Coor(:,2)-y).^2 + (Coor(:,3)-z).^2)<r;
Coor_withindistance_r = Coor(p,:);
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Wan Ji
2021-8-18
编辑:Wan Ji
2021-8-18
function [coor_num, neighbors_with_r] = Coordinates(X,Y,Z,Coor)
r = 1:10;
coor_num = zeros(length(r),1);
neighbors_with_r = cell(length(r),1);
for i = 1:1:length(r)
p = sqrt((Coor(:,1)-X).^2 + (Coor(:,2)-Y).^2 + (Coor(:,3)-Z).^2)<r(i);
Coor_withindistance_r = Coor(p,:);
coor_num(i) = size(Coor_withindistance_r, 1);
neighbors_with_r{i,1} = Coor_withindistance_r;
end
end
This may work, it returns the numbers of coordinates with different distance r (an array), and returns their coordinates. @sai sai
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Turlough Hughes
2021-8-18
编辑:Turlough Hughes
2021-8-18
The points which are within a radius, r, from the origin can be obtained as follows:
index = sum(X.^2,2) < r^2; % X is an n by 3 array of points
Xthresh = X(index,:);
Note, squaring r is more efficient than taking the square root for ALL of the points in X.
For a starting point other than the origin, e.g. p (1 by 3), points in X within a threshold radius r from the point p can be obtained as follows:
index = sum(X.^2 - p,2) < r^2;
Xthresh = X(index,:);
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