Need help with this Matlab script question? For loop!!
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I keep getting this error 'Attempted to access x(3); index out of bounds because numel(x)=2.' It's really frustrating!!!
采纳的回答
ES
2014-7-29
You have to define x(3) as well (It should be 2 right ?), and then run the loop from x=3 and change the order of statements inside the while loop, because you set x(k) and then increment k. so for the new incremented k, x(k) will not be defined yet.
Please check:
%%Determining the golden ratio in a fibonacci sequence clear,clc % Defining the first two elements in the sequence x(1) = 1;
x(2) = 1;
x(3) = 2;
k = 3;
while (abs(x(k)./x(k-1) - x(k-1)./x(k-2))>0.001)
k = k+1;
x(k) = x(k-1) + x(k-2);
end
更多回答（1 个）
Robert Cumming
2014-7-29
编辑：Robert Cumming
2014-7-29
It the start of your while loop the condition includes a check on x(3), hence why you get the error.
edit: you could fix it this way:
while true
x(k) = x(k-1) + x(k-2);
k = k+1;
if (abs(x(k)./x(k-1) - x(k-1)./x(k-2))>0.001)
break
end
end
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