0 个投票

i have a set of values for the force term "F" (in the equation my"+cy'+ky=F) saved in an excel file which i have recalled using:
F=xlsread('l&d.xlsx','O1:O300');
My main code looks something like:
y0=initial conditions
[tsol ysol]=ode15s('beam_function',[1:dt:T],y0);
plot(tsol,ysol);
whereas, my function code looks something like:
function [dy]=beam_function(t,y)
dy=[y(1:u-1);
inv(M)*(F-K*y(u:end)-C*y(1:u-1))]
The problem is that i want to recall each value of F at different time steps but i dont know how to do that, can anyone guide me?
Note: F here is not time dependent rather it has been taken from results obtained from a simulation software. Then what should be my approach?

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darova
darova 2021-8-24

0 个投票

You need to pass F into your ode function. Read more: LINK
for i = 1:length(F)
[t,y] = ode45(@(t,y)beam_function(t,y,F(i)),...)
end
function dy = beam_funciton(t,y,F)

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Bhanu Pratap Akherya
编辑：darova 2021-8-25
that helped, i have one more question
here is my main code:
clear all
clc
Ne=6;
l=1; %length
t=0.02; %thickness
b=0.02; %width
modulus=2e11; %(E)
area=b*t;
imoment=(b*((t)^3))/12;
Le=l/Ne; %length of element
Rho=7850; %density
%Element stiffness matrix
K1=(modulus*imoment/(Le^3))*[12,6*Le,-12,6*Le; ...
6*Le,4*Le*Le,-6*Le,2*Le*Le; ...
-12,-6*Le,12,-6*Le; ...
6*Le,2*Le*Le,-6*Le,4*Le*Le];
Kglobal=zeros(2*(Ne+1),2*(Ne+1));
M1=[156 22*Le 54 -13*Le;...
22*Le 4*Le*Le 13*Le -3*Le*Le;...
54 13*Le 156 -22*Le;...
-13*Le -3*Le*Le -22*Le 4*Le*Le]*(Rho*Le*b*t)/420;
Mglobal=zeros(2*(Ne+1),2*(Ne+1));
for ii=1:Ne
Kglobal(2*ii-1:2*(ii+1),2*ii-1:2*(ii+1))=Kglobal(2*ii-1:2*(ii+1),2*ii-1:2*(ii+1))+K1;
Mglobal(2*ii-1:2*(ii+1),2*ii-1:2*(ii+1))=Mglobal(2*ii-1:2*(ii+1),2*ii-1:2*(ii+1))+M1;
end
K=Kglobal;
K(1:2,:)=[];
K(:,1:2)=[];
M=Mglobal;
M(1:2,:)=[];
M(:,1:2)=[];
C=0.05*Kglobal;
C(1:2,:)=[];
C(:,1:2)=[];
K
M
C
u=(2*Ne)+1;
%dt=1/(max_freq*20);
dt=0.001;
T=300;
%Displacement initials
y0=zeros(2*(2*(Ne+1))-4,1);
% y0(1:2,:)=[];
% y0(u:u+1,:)=[];
y0(end-1,1)=0.5;
% t_array = a(1,:); % This is t array from xls file
F=xlsread('l&d.xlsx','O1:O300'); % This is F array from xls file
%% ode solver
for i = 1:length(F)
[tsol ysol]=ode15s(@(t, y) beam_function(t, y, F(i), K, M, C, u),[1:dt:T],y0);
end
ysol(:,u:end)=[];%eliminate velocity nodes 5001*12
size(ysol)
ii=1:2:(u-2); %eliminate angular displacement nodes
ysol(:,ii+1)=[]; %eliminating angular dis components
size(ysol)
%% plotting
plot(tsol,ysol(:,Ne))
here is my function
function [dy]=beam_function(t, y, F, K, M, C, u)
dy=[y(u:end);
M\(F-K*y(1:u-1)-C*y(u:end))]
I want force (F) to be applied on the last node. Can you tell me a way how i can do that?
darova
darova 2021-8-25
Did you try simply?
F(end) = 1000;
No, but won't this simply change my F matrix's last term to 1000?
darova
darova 2021-8-25
Exactly. Isn't that enough?
No, I meant how to apply the current F matrix on only the last column of y in ODE. Right now it is being applied on all the columns of y.
darova
darova 2021-8-29
编辑：darova 2021-8-29
Maybe you need another ode function
function [dy]=beam_function(t,y)
n = numel(y);
dy(n/2) = y(end);
dy(end) = inv(M)*(F-K*y(end)-C*y(end));
And solve it separately

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