loop with decrementing step

10 次查看(过去 30 天)
Good Day,
May I ask a question, how can I create loop that the output is like this (10 20 29 38 47 56 65 and so on) and (80 70 61 53 46 40 35 and so on) same in negative (-10 -20 -29 -38 -47 -56 -65 and so on) and (-80 -70 -61 -53 -46 -40 -35 and so on)
The start, end and step is variable
example I can start in 17 to 30 and start step is 5 to 0.125 just like this [17 (+5) 22 until 29.875 (+0.125) 30] same in negation
  2 个评论
Walter Roberson
Walter Roberson 2021-8-26
What would be the rule for that last example? How does the step of +5 get down to +0.125 ?
The other ones, the step just decreases by +1 each time for increasing series, or the step increases by 1 each time (from -9 to -8 to -7 and so on) for decreasing series... but how +5 gets to be +0.125 is not at all obvious.
Dennis M
Dennis M 2021-8-26
Thanks Sir Walter, I want start, end, and step to be variable and the step is decrementing with declare value when it reach the end value. Example the start step is 5 end of 0.125 when reach the desire end value. Illustrated code A= start:step:end A= 17:(linspace 5,0.125):30

请先登录,再进行评论。

采纳的回答

Walter Roberson
Walter Roberson 2021-8-26
start = 17;
step = linspace(5,0.125);
stop = 30;
ZZZZZZZZZ_intermediates = start + cumsum([0 step]);
if start <= stop
ZZZZZZZZZ_intermediates = ZZZZZZZZZ_intermediates(ZZZZZZZZZ_intermediates<=stop);
else
ZZZZZZZZZ_intermediates = ZZZZZZZZZ_intermediates(ZZZZZZZZZ_intermediates>=stop);
end
for loop_variable = ZZZZZZZZZ_intermediates
%body of the loop goes here
disp(loop_variable)
end
17 22 26.9508
You might notice that the loop ended before 29.875 . You asked for the increments to be linspace(5,0.125) but remember by default linspace() is a vector of 100 values -- so the first increment would be 5, the second would be about 4.9508, the third is about 4.9501, and so on. Those quickly add up to more than the stop point.
Your requirement to be able to specify an expression for the increments, leads to the possibility that your increments might have a mix of positive and negative numbers. A decision had to be made about what to do for the case where the steps increment past the endpoint but that steps with the opposite sign then take the value back to below the endpoint. Clearly values beyond the end point should not be included... but should you stop as soon as you pass the endpoint the first time, or should you allow for the value to come back?
I decided that since it should be permitted to allow a mix of increments while you are in range, that it would make the most sense to allow values to return back to range. So what I do is filter out the values that go beyond the stop-point -- leaving any that come back to the range. So with positive increments 5 for a while, and negative increments (say) 7, a sequence with start 1 and stop 20 and increments [5 5 5 5 -7 -7] might go [1 6 11 16 (OMITTED 21) 14 7] leaving [1 6 11 16 14 7] as the loop control values.
It might also be reasonable to argue that the sequence should never emit values "before" the start after having gone past it -- so 1:[5 5 5 5 -7 -7 -7]:20 with the logic posted above would give [1 6 11 16 14 7 0] but it would be reasonable to filter on start as well as stop giving loop values [1 6 11 16 14 7] ...
  13 个评论
Walter Roberson
Walter Roberson 2021-9-2
No, there is no point in my reading that code. It clearly does not answer the points I raised in https://www.mathworks.com/matlabcentral/answers/1441094-loop-with-decrementing-step#comment_1716959 . I have negative interest in trying again work out your requires by working backwards from your work.
If you want further assistance, you need to make clear you need the code to do. You have to ask the right question, because I am tired of giving answers to what you just maybe meant and then being told Yes / No without even a "Warmer / Colder" to guide me.
Dennis M
Dennis M 2021-9-2
Pardon Sir Walter I'm confusing also what the best code or possiblity to do, but you make it by example and I really appreciate that.
I combine your previous code and comment to other question. Now it's clear to me that important was the last step and just flip it.
Thanks Again!
I Hope You will answer my question again in the future

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Stress and Strain 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by