splitting cell array consists of string and numeric characters
显示 更早的评论
I have a cell array (n x 1). Each cell looks something like this:
* 2021 3 29 0 0 0.00000000
I need to remove * from each cell and split the cell array into 6 columns consist of double values. For example;
2021 3 29 0 0 0
2021 3 30 0 0 0
.
.
.
How I can do that?
采纳的回答
Use replace
S = {...}; % your n*1 cell array
S = arrayfun(@(i)replace(S{i},'*',''),1:1:numel(S),'uniform',false);
9 个评论
And if you want to transform S later to datetime then use'
DT = arrayfun(@(i)datetime(str2num(S{i})),(1:1:numel(S))')
sermet OGUTCU
2021-8-26
编辑：sermet OGUTCU
2021-8-26
Wan Ji
2021-8-26
S = {...}; % your n*1 cell array
S = arrayfun(@(i)num2str(str2num(replace(S{i},'*',''))),1:1:numel(S),'uniform',false);
Wan Ji
2021-8-26
Or you can do
S = {...}; % your n*1 cell array
S = arrayfun(@(i)replace(S{i},'* ',''),1:1:numel(S),'uniform',false);
sermet OGUTCU
2021-8-26
编辑：sermet OGUTCU
2021-8-26
Wan Ji
2021-8-26
S = arrayfun(@(i)num2str(str2num(replace(S{i},'*',''))),1:1:numel(S),'uniform',false);
DT = arrayfun(@(i)datetime(str2num(S{i})),(1:1:numel(S))');
DV = datevec(DT);
YourCelln6 = mat2cell(DV,ones(size(DV,1),1),ones(size(DV,2),1));
Wan Ji
2021-8-26
Wan Ji
2021-8-26
You may see n*6 cell is not so good at all compared with DT or DV
sermet OGUTCU
2021-8-26
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