Array indices must be positive integers or logical values for loop expression

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SL
SL 2021-8-27
评论： SL 2021-8-30
i do not know why but when I run this I get the error that array indicies must be positive, it is , isnt it ? Please help thanks
Nu = 300; % nu of samples
N = 700; % number of learning samp0les
D = 5; % some constant
cdot(1) = [100];
Co(1) = 10;
% initialize
%first derivate
x = [1.2 1.23 1.55 1.6 1.66 1.85 1.9 1.92 1.95 1.9544.....
1.9611 1.9626 1.9788 1.98 1.9822 1.9855 1.9899 1.925];
t = 1:60;
for i =0:100
cdot(i+1) = cdot(i) - Co(i) + (0.25*x./sqrt(D.*t(i)) + 0.5 ./ sqrt(D.*t(i)) ) .* exp(0.5.*x./sqrt(D.*t(i)));
end

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采纳的回答

TADA
TADA 2021-8-27
in Matlab array indices start from 1, not 0 like other languages.
You have more bugs in this script, but this error is due to starting your loop index from zero instead of 1

更多回答（1 个）

Image Analyst
Image Analyst 2021-8-27

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