Getting wrong results while calling a function.
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I have written a simple function. It takes two inputs, only when two inputs are equal the output should be zero.
function I = getI(E,Eg)
if (E<=1.5) && (E ~= Eg)
I=(500*E)/1.5;
elseif (E>1.5) && (E<=4) && (E ~= Eg)
I=500*(1-((E-1.5)/(4-1.5)));
elseif (E==Eg)
I=0;
end
end
Now the function works as expected most of times,but when the value of Eg is 1.38,1.39,1.4, 2.84 or 2.6 the code doesnot gives I=0 even when the value of Eg is equal to E. Example:
I tried changing the if conditions, changing their positions. No change. 
回答（1 个）
Rik
2021-9-2
1 个投票
Some numbers cannot be represented exactly in binary. You will either need to round both numbers to make sure they have the exact same representation, or compare the differences to a tolerance.
2 个评论
Asif Rahman
2021-9-2
Shouldn't this show wrong result also?
If not than can you please guide me about a different approach. Thanks.
Rik
2021-9-3
This shows the correct result, because the numbers are generated the same way.
If a number can't be represented exactly by a double, it might be represented slightly differently if the method of calculation is different, e.g. writing 1.4 directly and using the colon operator.
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2021-9-2
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