How do I create array of a function with for loop?
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Hi, I am trying to find a shorter and easier for my calculations. I have a in total 42 of 424x412 doubles for which I want to calculate the mean of all elements and build an array of the results that would be 42x1. So far I have done that the following way
B = [mean(X1,'all');mean(X2,'all');..mean(X42,'all')]
Since I have to calculate such arrays multiple times (I have do that for multiple sets of 42 arrays) I would much rather like to that in a for-loop..so far i have tried the following, which didn't work
for k = 1:42
B = mean('X(k)','all')
end;
can somebody help me?
I am a MATLAB rookie! :D
1 个评论
Stephen23
2021-9-7
You did not tell us the most important information: how did you get 42 numbered variables into the workspace?
Did you sit and write out their names by hand? Or generate them in a loop? Or load them from file?
In any case, that is where you need to fix your code, rather than trying to fix the problem later:
回答(2 个)
Steven Lord
2021-9-7
I have a in total 42 of 424x412 doubles
Can you do this? Yes.
Rather than having 42 individual variables why not make a 42-by-424-by-412 array?
2 个评论
Stephen23
2021-9-7
"And I also have to do that multiple times... The X in the example above stands for a month... I want to calculate that for all 12 months and over muliptle datasets "
Sure. That would be easy and very efficient using standard MATLAB coding, e.g. using indexing to access data in arrays (which could be container arrays). Is there any particular reason why you want to force yourself into writing slow, complex, obfuscated, inefficient code?
Mathieu NOE
2021-9-7
hello
it's not the best coding practice, but it works ...
clc
clearvars
% dummy data
X1 = rand([424,412]);
X2 = rand([424,412]);
X3 = rand([424,412]);
% main code
for k = 1:3
B(k) = mean(eval(['X' num2str(k)]),'all');
end;
plot(B,'*')
3 个评论
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