Interpolation problem with interp1
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Hello everyone:)
I have graphic with some missing data, so I interpolated my data vector to fill the gaps but I have this error message " Brace indexing is not supported for variables of this type." and I could not fond the error! So here is the code I used:
for i=1:length(t0)
R{i}=interp1(t{i},R{i},t0,'linear');
end
thanks in advence😊
采纳的回答
Image Analyst
2021-9-7
Are t and R cell arrays, tables, or just regular double numerical arrays? If they're just regular numerical arrays, use parentheses, not braces. Please read the FAQ to know when you need to use braces, parentheses, or brackets:
If they are just regular vectors, you don't need a for loop, you can simply do
% t is x, R is y, and t0 are the new x values that you want y values for.
interpolatedY = interp1(t, R, t0, 'linear');
R = interpolatedY; % If you want to replace your existing R, then do this.
更多回答（1 个）
Not sure what your R vector represents but it seems like you are trying to use a loop to interpolate within a one-dimensional array. This is something Matlab does at the array level itself without the need for a loop.
If you look up help interp1 , there's an example of this.
X = 0:10;
V = sin(X);
Xq = 0:.25:10;
Vq = interp1(X,V,Xq);
plot(X,V,'o',Xq,Vq,':.')
X and V have 11 elements.
Xq and the interpolated Vq have 41 elements.
No looping required.
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