rounding elements in array to nearest 0.25

2011 8 25
3 个回答
回答已采纳
更新时间：2023 12 4
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3 个投票

i need to round off some numbers to nearest quarter , with an option to round up or round down to nearest quarter
for e.g. For an array for (5,1) with following values
1373.698
1385.024
1394.82
1400.436
1396.532
output for rounding up to closest 0.25 will result in
1373.75
1385.25
1395.00
1400.50
1396.75
output for rounding down to closest 0.25 will be
1373.50
1385.00
1394.75
1400.25
1396.50
I am not sure how to create such a function which gives this output, please help .

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 采纳的回答

Friedrich
Friedrich 2011-8-25

4 个投票

Hi,
I think you are looking for:
in = [1373.698
1385.024
1394.82
1400.436
1396.532];
%round up
up = floor(in) + ceil( (in-floor(in))/0.25) * 0.25
%round down
down = floor(in) + floor( (in-floor(in))/0.25) * 0.25

更多回答（2 个）

Walter Roberson
Walter Roberson 2011-8-25

10 个投票

The previous answers look more complex than needed
%round up
up = ceil(in * 4) / 4;
%round down
down = floor(in * 4) / 4;

2 个评论
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SL
SL 2016-10-25
编辑：SL 2016-10-25
Can you make this a single function, please? - - It would be then a complete answer to the question, at least for me. I extended my case here https://se.mathworks.com/matlabcentral/answers/309097-how-to-round-up-to-closest-0-0-or-0-5-in-array

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4 个投票

If you want to round to the nearest 0.25 both up and down, then do:
%roudn to nearest 0.25
updown = round(in * 4)/4;

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