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Binning returns zero values/column vector of 0's

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Zhou Ci
Zhou Ci 2021-9-9
评论： Image Analyst 2021-9-28
Hi all,
I have a table containing values from 3 parameters, T, V and P. My assignment says;
-For 1C interval you'll have several pixels fall in this interval.
-Calculate the median R for those pixels within this 1C.
-For this 1K interval, you would have several pixels.
I tried to do this but it returns a column vector of zero. Data is attached. Kindly suggest me how to accomplish it. Thank you.
temperature_rounded=round(Temp,0);
T=unique(temperature_rounded);
Z=NaN(size(T));
%%
for n=1:numel(T)
L= T==T(n); %select all positions where the rounded temperature is a specific value
Z(n)=median(Radius(L));%calculate the median for this selection
end
  1 个评论
Image Analyst
Image Analyst 2021-9-28
Code snippet is attached, but no data. Did you forget to attach it?
Isn't a 1 degree Kelvin interval the same as a 1 degree Celcius interval? So why wouldn't the "number of pixels" be the same for the two?
Have you learned of the functions histogram() and splitapply()?

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回答（1 个）

Walter Roberson
Walter Roberson 2021-9-9
编辑：Walter Roberson 2021-9-9
L = temperature_rounded == T(n);

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