Pressure drop script is not running

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Jayashri Patil 2021-9-13

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1451949-pressure-drop-script-is-not-running

回答： Rik 2021-9-13

采纳的回答： Rik

clear "all"

clc

N=input('enter the number of different pipe size: ');

for i=1:N

d(i)=input('enter the diamter of pipe %s(m): ',i);

l(i)=input('enter the length of pipe %s(m): ',i);

Kl(i)=input('enter the no of bends %s(m): ',i);

end

rho=input('enter the value of density: ');

v(i)=input('enter the value of v(i): ');

Mu=input('enter the value of viscocity: ');

Q=input('enter the flowrate: ');

eps=input('enter the epsilon: ');

for i=1:N

A(i)=pi*D(i)*D(i)/4;

v(i)=Q/A(i);

ReynoldsNumber1=Rho*v(i)*D(i)/Mu;

if ReynoldsNumber1 <2300

f1=64/ReynoldsNumber1;

elseif ReynoldsNumber1 >4000

c=@(f(i))(1/sqrt f(i))+ 2*(log10((eps/3.7*D(i))+(2.51/(ReynoldsNumber1*sqrt f(i))));

f(i)=fzero(c,[0.01,0.02]);

end

deltap(i)=(f(i)*(L(i)/D(i))*((Rho*v(i)*v(i))/2)/1000); % pressure drop in kpa

KL(i)=sum(KL(i)entrance+KL(i)elbow+KL(i)valve+KL(i)exit);

HL(i)=(f(i)*(L(i)/D(i))+KL(i)*v(i)*v(i)/2*g); %head loss in m

end

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Rik 2021-9-13

What are you trying to do? Did you read the documentation for the input function? You seem to be using it as if it is sprintf.

Jayashri Patil 2021-9-13

I am trying for calculate pressure drop taking different type of diameter from user.but there is error.

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Answer 1

Rik 2021-9-13

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在 MATLAB Online 中打开

If you have problems with a function, you should really check the documentation.

The input function does not work like you expect it to. It will not use later input variables to compose a string. You need to use sprintf to do that. You should also add the 's' parameter to your input call. That way you get the actual text your user entered. You can then use str2double to convert to a number. That will prevent users from using variable names that you're using as a parameter.

tmp=input(sprintf('enter the diamter of pipe %d(m): ',i),'s');
tmp=str2double(tmp);
if isnan(tmp)
    error('variable entered is not a valid number')
end