If same value apperas in array count +1

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First Last
First Last 2021-9-14
评论： First Last 2021-9-14
Hello Guys,
I have an array with nx1, now i need a code to count + 1 if the same value apperas later in the array, for example:
input = [ 1 2 3 4 1 2 3 4 1 2 3 4 ];
output = [ 1 1 1 1 2 2 2 2 3 3 3 3];
Thank you

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采纳的回答

Walter Roberson
Walter Roberson 2021-9-14
Ran in:
input = [ 1 2 3 4 1 2 3 4 1 2 3 4 ];
output = sum(triu(input' == input))
output = 1×12
1 1 1 1 2 2 2 2 3 3 3 3

更多回答（1 个）

KSSV
KSSV 2021-9-14
input = [ 1 2 3 4 1 2 3 4 1 2 3 4 ];
a = reshape(input,[],3)' ;
[c,ia,ib] = unique(a,'rows') ;
ib

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