How to find uaci by fixing one image and changing the other?
2 次查看(过去 30 天)
显示 更早的评论
The code for uaci for two images A and B.
uaci= sum( abs( double(A(:)) - double(B(:)) ) ) / num_of_pix / largest_allowed_val;
If A is a fixed image and there are differnt various B images say '50' then how to find uaci by fixing image A and varying B.
All the B images are in one folder.
0 个评论
采纳的回答
KSSV
2021-9-16
A = imread('whatever_is_A') ;
B_images = dir('*.png') ; % you are in the folder of images and give extension
N = length(B_images) ;
uaci = zeros(N,1) ;
for i = 1:N
B = imread(B_images(i).name) ;
uaci(i) = sum( abs( double(A(:)) - double(B(:)) ) ) / num_of_pix / largest_allowed_val;
end
2 个评论
KSSV
2021-9-16
Are you in the same folder where the image is present? What is B_images class? What is value of N? Are you giving the extension of the image properly?
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!