Binning data into 1000 bins between values
4 次查看(过去 30 天)
显示 更早的评论
Hi all,
I have 75,000 values and I'd like to bin them into 1000 bins between 0.985 and 1.030. Is this possible and if so how?
Regards
Tim
0 个评论
回答(1 个)
Image Analyst
2021-9-21
Description
Y = discretize(X,edges) returns the indices of the bins that contain the elements of X. The jth bin contains element X(i) if edges(j) <= X(i) < edges(j+1) for 1 <= j < N, where N is the number of bins and length(edges) = N+1. The last bin contains both edges such that edges(N) <= X(i) <= edges(N+1).
[Y,E] = discretize(X,N) divides the data in X into N bins of uniform width, and also returns the bin edges E.
[Y,E] = discretize(X,dur), where X is a datetime or duration array, divides X into uniform bins of dur length of time. dur can be a scalar duration or calendarDuration, or a unit of time. For example, [Y,E] = discretize(X,'hour') divides X into bins with a uniform duration of 1 hour.
[___] = discretize(___,values) returns the corresponding element in values rather than the bin number, using any of the previous input or output argument combinations. For example, if X(1) is in bin 5, then Y(1) is values(5) rather than 5. values must be a vector with length equal to the number of bins.
2 个评论
Steven Lord
2021-9-21
If you also want the counts of how many elements fall into each bin I'd use histcounts with three outputs.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Data Type Conversion 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!