How to find real and complex roots for a nonlinear equation

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Marco Dellacasa
Marco Dellacasa 2021-9-21
评论： Marco Dellacasa 2021-9-22
Hi everyone,
I have to solve this eqution numerically:
the only variable is H and it tipically gives two complex roots and one real root, I've read that fzero is not suitable in this case, could anyone give mi any tips please?
Thank you

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回答（1 个）

Viranch Patel
Viranch Patel 2021-9-22
For simplicity I have taken a simple function which has complex roots.
syms H
eq=H^2 + 1;
solve(eq==0,H)
You can specify your equation in H like this and this should give you the roots correctly.
  1 个评论
Marco Dellacasa
Marco Dellacasa 2021-9-22
Warning: Unable to solve symbolically. Returning a numeric solution using vpasolve.
> In sym/solve (line 304)
In prova_Irvine (line 15)
ans =
-8530666.6665264117623777679822889
>>
Unfortunately it didn't work, I know a priori that usually this equation has in total 3 roots: 2 complex and 1 real, maybe the problem is that I have both real and complex roots to find instead only real or only complex roots?

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