who to write this function in another way?

Question

Mohammad Alhaddad 2021-9-22

0
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https://ww2.mathworks.cn/matlabcentral/answers/1458229-who-to-write-this-function-in-another-way

回答： Steven Lord 2021-9-22

在 MATLAB Online 中打开

I did this function but I didn't want like this long. I try to put in MATLAB Function in simulink

I want like this but I did not where my mistake?

outputvalue = map(sensorValue, low input , high input , low output , high input);

y = map(u, -1 , 1 , 0 , 0.5);

that what I did

function y = fcn(u)
if  u <(-0.9)
    y=0.25;
elseif  u < (-0.8)
    y=0.20;
elseif  u < (-0.6)
    y=0.15;
elseif  u < (-0.4)
    y=0.10;
elseif  u < (-0.2)
    y=0.05;
elseif    u < 0.2
    y=0;
elseif    u < 0.4
    y=0.30;
elseif  u < 0.6
    y=0.35;
elseif  u < 0.8
    y=0.40;
elseif  u < 0.9
    y=0.45;
elseif  u < 1.5
    y=0.50;
else 
    y=1;
    
end 

2 个评论
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KSSV 2021-9-22

在 MATLAB Online 中打开

u < (-0.8)

can be

u < -0.8

Mohammad Alhaddad 2021-9-22

i know but I didnot want the second code I want convert to this

outputvalue = map(sensorValue, low input , high input , low output , high input);

y = map(u, -1 , 1 , 0 , 0.5);

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Answer 1

Chunru 2021-9-22

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1458229-who-to-write-this-function-in-another-way#answer_792459

在 MATLAB Online 中打开

fcn(-5)
ans = 0.2500
fcn(.34)
ans = 0.3000
fcn(4)
ans = 1
function y = fcn(u)
x0 = [-inf  -0.9  -0.8  -0.6  -0.4  -0.2  0.2   0.4   0.6   0.8   0.9   1.5];
y0 = [0.25  0.20   0.15  0.10  0.05  0    0.30  0.35  0.40  0.45  0.50  1  ];
idx = find(u > x0, 1, 'last' );
y = y0(idx);
end 