Have problem in solution

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Ratchapon Nilprapa 2021-9-23

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https://ww2.mathworks.cn/matlabcentral/answers/1459124-have-problem-in-solution

评论： Rik 2021-9-26

采纳的回答： Rik

I'm new to Matlab and I have a problem with this solution on line 14. Please give me for any advice. Thank you

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John D'Errico 2021-9-23

When you post code, post it as text, not a picture of text. Otherwise, you force someone to type in your entire code, unless they can see an obvious error. If you want help, then make it easy for someone to help you.

Ratchapon Nilprapa 2021-9-26

My apologize, thank you for your advise Mr.John D'Errico.

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Answer 1

Rik 2021-9-23

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编辑：Rik 2021-9-23

It looks like you want different things to happen depending on the value of Erf: for every element smaller than 2 you want y to have some value, and for other elements you want a different calculation.

But that is not what you tell Matlab to do. You see all those orange squiggly lines? Those are warnings. You should read them and deal with them. In this case I suspect this is the solution: use a for-loop.

Erf=[0.2 0.6 0.7333];
y=NaN(size(Erf));
for n=1:numel(Erf)
    if Erf(n)<2
        y(n)=(-0.3725*Erf(n)^2);%and the rest the of the line
    else
        y(n)=(-0.0109*Erf(n)^2);%and the rest the of the line
    end
end

You can also do this in one go with logical indexing, in which case you need to use element-wise operations (.^ instead of ^, and similarly for multiplication and division).

Erf=[0.2 0.6 0.7333];
y=NaN(size(Erf));
L=Erf<2;
y(L)=-0.3725*Erf(L).^2;
L=~L;
y(L)=-0.0109*Erf(L).^2;

These two blocks of code yield the same result.

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Ratchapon Nilprapa 2021-9-26

Thanks for your kindness that you explain to me clearly, Rik.

Rik 2021-9-26

You're welcome. If either solution solved your issue, please click the 'accept answer' button. If you feel the other answer helped as well, feel free to click the vote button.

If neither solved your problem, feel free to comment with your remaining issues.

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Answer 2

Walter Roberson 2021-9-23

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https://ww2.mathworks.cn/matlabcentral/answers/1459124-have-problem-in-solution#answer_793444

编辑：Walter Roberson 2021-9-23

Erf=[0.2 0.6 0.7333];

Erf is a vector.

y=(-0.3725*(Erf)^2)+(1.2144*(Erf))+(0.0006);

You have Erf^2 . But in MATLAB, the ^ operator is repeated matrix multiplication -- so Erf^2 is (Erf*Erf) where * is the algebraic matrix multiplication operator, also known as Inner Product. For Inner Product A*B, the number of columns of A (the first operand) must be the same as the number of rows of B (the second operand) . You hae a 1 x 3 vector, so you effectively have (1 x 3) * (1 x 3), but the number of columns in the first operand, 3, does not match the number of rows in the second (1).

You probably want the element-by-element power operator, which in MATLAB is the .^ operator

y=(-0.3725*(Erf).^2)+(1.2144*(Erf))+(0.0006);

Be careful: your line 19 completely overwrites y, overwriting the value assigned to y in line 18.

Note: it is easier for the volunteers to assist you if you post code, instead of posting pictures of code. Don't make the volunteers type out the code by hand in order to test it or point out which parts of it have difficulties.