solve the equation for a large frequency range

Question

Tasin Nusrat 2021-9-26

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https://ww2.mathworks.cn/matlabcentral/answers/1460884-solve-the-equation-for-a-large-frequency-range

评论： Tasin Nusrat 2021-9-26

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I want to solve the below equation for the frequency range of 1Khz to 100MHz.

the equation is factor=Rsh/(Rsh+j*2*pi*frequency*Lsh)

here,

Rsh=0.01*pi

and

Lsh=5*10^-9

. But when I run the code it shows matrix mismatch

freq=1e+3:1e+8;%frequency range
Rsh=0.01*pi;
d=Rsh+(2*pi*freq*i*5*10^-9);
factor=Rsh/d;

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Answer 1

Walter Roberson 2021-9-26

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 Rsh=0.01*pi
Rsh = 0.0314
Lsh=5*10^-9
Lsh = 5.0000e-09
freq=1e+3:1e+8;%frequency range
Rsh=0.01*pi;
d=Rsh+(2*pi*freq*i*5*10^-9);
factor = Rsh ./ d;

In MATLAB, the / operator is "matrix right divide". Rsh/d is roughly equivalent to Rsh * pinv(d) but with some restrictions about the sizes; the * indicated here is algebraic matrix multiplication, "inner product".

What you wanted was element-by-element division, which in MATLAB is the ./ operator.

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Walter Roberson 2021-9-26

在 MATLAB Online 中打开

Rsh=0.01*pi
Lsh=5*10^-9
freq=1e+3:1e+8;%frequency range
Rsh=0.01*pi;
d=Rsh+(2*pi*freq*i*5*10^-9);
factor = Rsh ./ d;
b = 2 .* pi .* 3.5e-12 .* i .* factor .* freq;