Is there a way to avoid this inaccuracy when converting an string to a double and then to an unsigned int? I have tried using str2num() but get the same result.Thanks!

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Guillermo Camacho
Guillermo Camacho 2021-9-28
回答： Walter Roberson 2021-9-28
uint64(str2double('132697151393876469'))
%ans =
% uint64
% 132697151393876464
% note that the ans is the same for inputs 1326971513938764XX, where XX is in the range (57-71)

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采纳的回答

Walter Roberson
Walter Roberson 2021-9-28
Ran in:
format long g
A = sscanf('132697151393876469', '%lu')
A = uint64
132697151393876469
class(A)
ans = 'uint64'

更多回答（1 个）

the cyclist
the cyclist 2021-9-28
The reason for this is that MATLAB uses double-precision arithmetic by default, which will typically give approximately 15 decimal digits of precision.
One possibility, if you have the Symbolic Math Toolbox, is to use variable-precision arithmetic.

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