Proper classification of variables in parfor loop

2 次查看（过去 30 天）
Henrik
Henrik 2014-8-5
评论： Henrik 2014-8-6
Hi there I have a loop that I would like to run with parfor. A simplified version of the code is
parfor qx_index=1:Nsx*Nx
for qy_index=1:Nsx*Nx
chi(qx_index,qy_index,:)=function(other_variables,qx_index,qy_index)
end
end
When I run the code I get the following error:
Error: The variable chi in a parfor cannot be classified.
I cannot figure out why this doesn't work - help?

请先登录，再回答此问题。

回答（1 个）

Sean de Wolski
Sean de Wolski 2014-8-5
编辑：Sean de Wolski 2014-8-5
What you have above works fine for me (filling in a few of the blanks)...
chi = zeros(2,3);
parfor qx_index=1:2
for qy_index=1:3
chi(qx_index,qy_index,:)=afunction(qx_index,qy_index)
end
end
And
function z = afunction(y,x)
z = y*x;
  3 个评论
显示 1更早的评论
Adam
Adam 2014-8-5
There are a number of rules surrounding the functions you can use in a parfor loop. For example you cannot use nested functions or non-transparent functions like eval. Maybe your function does not meet these criteria?
Henrik
Henrik 2014-8-6
Uhuh, it is a rather complicated function, so that might be the issue. On the other hand, it works if I do
for qx_index=1:Nsx*Nx
parfor qy_index=1:Nsx*Nx
chi(qx_index,qy_index,:)=function(other_variables,qx_index,qy_index)
end
end

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Parallel for-Loops (parfor) 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by