Finding error like unrecognized function or variable ' tridiagonal'

1 次查看(过去 30 天)
Program:
% solution of 2D elliptical solution
% using Line Over Relaxation Method(LSOR)
% ep is accepted error%Tridiag: Tridiagonal equation zsolver banded system
clc;
clear all;
eps = 0.001;
omega = input(' enter the omega value: ');
beta = input (' enter the beta value: ');
n= 10000;
nx = 21;
ny = 42;
T(1:nx, 1:ny-1) = 0;
TN(1:nx, 1:ny-1) = 0;
T(1:nx, ny)= 100;
TN(1:nx, ny) = 100;
% its number of iteration
coeff = ( 2*(1+beta^2));
for iterations = 1:n
for j = 2:ny-1
a(1:nx-2) = -coeff;
b(1:nx-3)= omega;
c(1:nx-3)= omega;
for i = 2:nx-1
r(i-1) = - coeff*(1-omega)*T(i,j)-omega*beta^2*T(i,j+1)-omega*beta^2*TN(i,j-1);
end
r(1)= r(1)-omega*TN(1,j);
r(nx-2)= r(nx-2)-omega*TN(nx,j);
y = tridiagonal(c,a,b,r);
for k = 1:nx-2
TN(k+1,j)= y(k);
end
end
error = abs(TN-T);
totalerror = sum(error,'all');
if totalerror <= eps
break
end
T=TN;
end
iterations;
contour(TN');
RESULTS;
enter the omega value: 1.3
enter the beta value: 1
Unrecognized function or variable 'tridiagonal'.
Error in LSOR (line 28)
y = tridiagonal(c,a,b,r);
  4 个评论
C B
C B 2021-10-2
Plus i have changed a part of code please check if its as per requirement or not
% b(1:nx-3)= omega;
% c(1:nx-3)= omega;
b(1:nx-2)= omega;
c(1:nx-2)= omega;

请先登录,再进行评论。

采纳的回答

C B
C B 2021-10-2
编辑:C B 2021-10-2
function main
% solution of 2D elliptical solution
% using Line Over Relaxation Method(LSOR)
% ep is accepted error%Tridiag: Tridiagonal equation zsolver banded system
clc;
clear all;
eps = 0.001;
omega = input(' enter the omega value: ');
beta = input (' enter the beta value: ');
n= 10000;
nx = 21;
ny = 42;
T(1:nx, 1:ny-1) = 0;
TN(1:nx, 1:ny-1) = 0;
T(1:nx, ny)= 100;
TN(1:nx, ny) = 100;
% its number of iteration
coeff = ( 2*(1+beta^2));
for iterations = 1:n
for j = 2:ny-1
a(1:nx-2) = -coeff;
% b(1:nx-3)= omega;
% c(1:nx-3)= omega;
b(1:nx-2)= omega;
c(1:nx-2)= omega;
for i = 2:nx-1
r(i-1) = - coeff*(1-omega)*T(i,j)-omega*beta^2*T(i,j+1)-omega*beta^2*TN(i,j-1);
end
r(1)= r(1)-omega*TN(1,j);
r(nx-2)= r(nx-2)-omega*TN(nx,j);
y = Tridiagonal(c,a,b,r);
for k = 1:nx-2
TN(k+1,j)= y(k);
end
end
error = abs(TN-T);
totalerror = sum(error,'all');
if totalerror <= eps
break
end
T=TN;
end
iterations;
contour(TN');
end
function x = Tridiagonal(e,f,g,r)
% Tridiagonal: Tridiagonal equation solver banded system
% x = Tridiagonal(e,f,g,r): Tridiagonal system solver.
% input:
% e = subdiagonal vector
% f = diagonal vector
% g = superdiagonal vector
% r = right hand side vector
% output:
% x = solution vector
n=length(f);
% forward elimination
for k = 2:n
factor = e(k)/f(k-1);
f(k) = f(k) - factor*g(k-1);
r(k) = r(k) - factor*r(k-1);
end
% back substitution
x(n) = r(n)/f(n);
for k = n-1:-1:1
x(k) = (r(k)-g(k)*x(k+1))/f(k);
end
end
  3 个评论
Aman Murkar
Aman Murkar 2021-10-2
thanks I got iterations too by doing some changes thanks for helping me.
Now the main part comes that can you tell me specifically what mistakes do i did as i am just learning matlab and how I can avoid such mistakes? Hope you will guide me.
Thanks again

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Graphics Object Programming 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by