fprintf does not save all the data
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In my workspace, I have a 1x1 struct named modes. It has three fields called x,y,z. Each field is 1x46000 and each cell is a number in exponential format. I would like to save the x array to a .dat file. So I did the following
id = fopen('modes_x.dat', 'wt+');
for i = 1:size(modes.x,1)
fprintf(fid, '%s\r\n', modes(i,1).x)
end
fclose(fid)
Only 20566 values are saved to file. Beyond 20566, there are about 18000 zeros followed by more non-zero numbers. Somehow, fprintf stops saving data when it hits the zeros.
I tried replacing %s with %e but the output is blank.
Does anyone know what I am missing here? Too bad there is no option in the menu bar for such a simple task.
Thank you,
Vahid
采纳的回答
Walter Roberson
2021-10-4
0 个投票
When you use fprintf() with a %s format and ask to display a numeric value, then:
- if the value to be converted is a non-negative integer, including 0, then uint16() of the value would be taken, and that would be used as the character code. These days, mostly that would act as a Unicode character code, but that could vary depending on exactly how the file was opened. For example, integer 65 would be come character code 65, which is the character code for 'A' so A return linefeed would be output. In this case, the code would not output the characters '6' '5'
- otherwise, if the value has a fraction or is negative, %s does not warn but instead uses a %.6e format.
In the case of 0, char(0) would be emitted, and the \r\n would be emitted. But binary 0 in particular can mess up displays, depending how it is coded.
更多回答（1 个）
Vahid Askarpour
2021-10-4
0 个投票
3 个评论
Walter Roberson
2021-10-4
Why are you using a %s format to try to output double precision numbers?
Vahid Askarpour
2021-10-4
Vahid Askarpour
2021-10-4
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