If the date is represented as a floating point numeric class, why can't you just multiply it by the appropriate value? -- or are you just looking at the number expressed in scientific notation?
format long
D = 1.1223344444 % assuming the number is as described
D = D.*1E5 % the number is now as requested, but it displays in scientific notation
fprintf('%.5f\n',D) % display it differently (it's still the same number)
