Replacing sym with function handle

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Bathala Teja
Bathala Teja 2021-10-5
评论： Alan Stevens 2021-10-5
Ran in:
I gave my script below. In order to get my result i used 'sym' function.
But i want to implement without symbolic math toolbox, how to implement the same script with function handles?
syms phi
w = 2;
Nr = 20;
nr = sym(zeros(1, Nr));
wr = sym(zeros(1, Nr));
for n = 1:Nr
for i = 1:w
Awr = 50*(cos(i*2)-cos(i*9));
nr(1, n) = nr(1, n)+Awr*cos(i*(phi+2*n));
end
wr(1, n) = nr(1, n);
end
NR = vpa(nr+(56*3/2), 4)
NR = 
WR = vpa(wr, 4)
WR = 

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回答（1 个）

Alan Stevens
Alan Stevens 2021-10-5
Ran in:
Do you mean something like this?
phi = pi/3;
[nr, wr] = fn(phi);
disp(phi)
1.0472
disp(nr(4)+56*3/2)
13.1554
disp(wr(4))
-70.8446
function [nr, wr] = fn(phi)
w = 2;
Nr = 20;
nr = zeros(1, Nr);
wr = zeros(1, Nr);
for n = 1:Nr
for i = 1:w
Awr = 50*(cos(i*2)-cos(i*9));
nr(1, n) = nr(1, n)+Awr*cos(i*(phi+2*n));
end
wr(1, n) = nr(1, n);
end
end
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Bathala Teja
Bathala Teja 2021-10-5
After forming these set functions in nr, i want to integrate all the functions w.r.t phi individually.
If i dont get in function handles then how to integrate?
Alan Stevens
Alan Stevens 2021-10-5
You can use trapz. For example:
philo = 0;
phihi = pi;
phi = linspace(philo, phihi, 100);
dphi = (phihi-philo)/99;
nr = zeros(numel(phi),20);
wr = zeros(numel(phi),20);
Integral_nr = zeros(1,20);
Integral_wr = zeros(1,20);
for m = 1:numel(phi)
[nr(m,:), wr(m,:)] = fn(phi(m));
end
for k = 1:20
Integral_nr(k) = trapz(nr(:,k))*dphi;
end
plot(1:20,Integral_nr,'--o'),grid
xlabel('1:Nr'), ylabel('Integrals of nr')
function [nr, wr] = fn(phi)
w = 2;
Nr = 20;
nr = zeros(1, Nr);
wr = zeros(1, Nr);
for n = 1:Nr
for i = 1:w
Awr = 50*(cos(i*2)-cos(i*9));
nr(1, n) = nr(1, n)+Awr*cos(i*(phi+2*n));
end
wr(1, n) = nr(1, n);
end
end

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