Replacing sym with function handle
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I gave my script below. In order to get my result i used 'sym' function.
But i want to implement without symbolic math toolbox, how to implement the same script with function handles?
syms phi
w = 2;
Nr = 20;
nr = sym(zeros(1, Nr));
wr = sym(zeros(1, Nr));
for n = 1:Nr
for i = 1:w
Awr = 50*(cos(i*2)-cos(i*9));
nr(1, n) = nr(1, n)+Awr*cos(i*(phi+2*n));
end
wr(1, n) = nr(1, n);
end
NR = vpa(nr+(56*3/2), 4)
WR = vpa(wr, 4)
回答（1 个）
Do you mean something like this?
phi = pi/3;
[nr, wr] = fn(phi);
disp(phi)
disp(nr(4)+56*3/2)
disp(wr(4))
function [nr, wr] = fn(phi)
w = 2;
Nr = 20;
nr = zeros(1, Nr);
wr = zeros(1, Nr);
for n = 1:Nr
for i = 1:w
Awr = 50*(cos(i*2)-cos(i*9));
nr(1, n) = nr(1, n)+Awr*cos(i*(phi+2*n));
end
wr(1, n) = nr(1, n);
end
end
4 个评论
Bathala Teja
2021-10-5
Alan Stevens
2021-10-5
Your question specified not using the symbolic toolbox!
I chose a single value of phi as an example. You can pass as many values of phi as you like to the function, by using a loop.
Bathala Teja
2021-10-5
Alan Stevens
2021-10-5
You can use trapz. For example:
philo = 0;
phihi = pi;
phi = linspace(philo, phihi, 100);
dphi = (phihi-philo)/99;
nr = zeros(numel(phi),20);
wr = zeros(numel(phi),20);
Integral_nr = zeros(1,20);
Integral_wr = zeros(1,20);
for m = 1:numel(phi)
[nr(m,:), wr(m,:)] = fn(phi(m));
end
for k = 1:20
Integral_nr(k) = trapz(nr(:,k))*dphi;
end
plot(1:20,Integral_nr,'--o'),grid
xlabel('1:Nr'), ylabel('Integrals of nr')
function [nr, wr] = fn(phi)
w = 2;
Nr = 20;
nr = zeros(1, Nr);
wr = zeros(1, Nr);
for n = 1:Nr
for i = 1:w
Awr = 50*(cos(i*2)-cos(i*9));
nr(1, n) = nr(1, n)+Awr*cos(i*(phi+2*n));
end
wr(1, n) = nr(1, n);
end
end
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2021-10-5
2021-10-5
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