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plotting equation which is function of 2 variable

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RJS
RJS 2021-10-6
评论： RJS 2021-10-9
I have one equation in terms of 2 variable A,B, I want to plot magnitude vs phase for different value of A and B .
i don't know how to do this . i was trying but it won't work
for A = -20:1:20
for B = -20:1:20
g=(1+i*B)/(1+i*A);
M=20*log10(abs(g)); %Magnitude matrix of Compensator
M = round(M,2);
P =rad2deg(angle(g)); %Phase Matrix of compensator
P = round(P,2);
plot(P,M);
hold on
end
end
trying to plot this figure
then
Find value of A and B for particualr value of phase and magnitude.

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采纳的回答

Cris LaPierre
Cris LaPierre 2021-10-6
Ran in:
Your code is close. I would take advantage of meshgrid instead of the for loops. Here's what I get making that change. Also, there is no need to round.
[A,B] = meshgrid(-20:1:20);
g=(1+i*B)./(1+i*A);
M=20*log10(abs(g)); %Magnitude matrix of Compensator
P=rad2deg(angle(g)); %Phase Matrix of compensator
plot(P,M,'k')
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Cris LaPierre
Cris LaPierre 2021-10-8
编辑：Cris LaPierre 2021-10-8
Ran in:
Perhaps try adding an assumption that a and b are real.
syms a b real
g=(1+i*b)/(1+i*a);
E = [20*log10(abs(g)) == 10, rad2deg(angle(g)) == 12];
S = vpasolve(E,a,b)
S = struct with fields:
a: 3.1836585625055579563412070062939 b: 10.505085360250508538864040773687
Now test the result to see if it results in the expected M and P values.
A=double(S.a);
B=double(S.b);
g=(1+i*B)./(1+i*A);
M=20*log10(abs(g)) % Should be 10
M = 10.0000
P =rad2deg(angle(g)) % Should be 12
P = 12.0000

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