Count consecutive elements in an array

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Debraj Midya
Debraj Midya 2021-10-6
评论： Mathieu NOE 2021-10-7
suppose i have an array like: A = [1 1 1 1 2 2 2 4 4 4 4 1 1 1 1 2]
I want the result in this form, B = [4 3 4 4 1].
or something like this will be best: B = [4 1; 3 2; 4 4; 4 1; 1 2]. First colums contains the number of entry and the second colums contains the entry itself.
Kindly help.

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Mathieu NOE
Mathieu NOE 2021-10-6
hello
try this :
A = [1 1 1 1 2 2 2 4 4 4 4 1 1 1 1 2];
% A = [1 2 2 4 4 1 1 2];
%% main code
p=find(diff(A)~=0);
s1 = [p(1) diff(p) numel(A)-p(end)];
s2 = A(cumsum(s1));
B = [s1' s2'] % First colums contains the number of entry and the second colums contains the entry itself

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