How to compute frequency of rows for submatrices?

Question

MRC 2014-8-8

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/146844-how-to-compute-frequency-of-rows-for-submatrices

编辑： Azzi Abdelmalek 2014-8-8

I have a matrix D which is a concatenation of 4 matrices of 3 rows (breaks added for clarity). I would like to construct a matrix C reporting the unique rows within the total matrix D listed for each of the sub-matrices of D with a count of how many times they occur.

    D=[1 0 1 1; 
       0 1 1 1; 
       1 1 0 1; 
       --------
       1 1 0 1; 
       1 1 0 1; 
       0 1 1 1; 
       --------
       1 1 1 0; 
       0 1 1 1; 
       1 0 1 1;
       -------- 
       1 0 1 1; 
       1 0 1 1; 
       1 1 0 0]

So for the above matrix, there are 5 unique rows:

So breaking those 5 rows into the 4 sub-matrices with counts of occurrence within them it would be:

    C=[1 0 1 1  1; 
       0 1 1 1  1; 
       1 1 0 1  1; 
       1 1 1 0  0; 
       1 1 0 0  0; 
       --------
       1 0 1 1  0; 
       0 1 1 1  1; 
       1 1 0 1  2; 
       1 1 1 0  0; 
       1 1 0 0  0; 
       ----------
       1 0 1 1  1; 
       0 1 1 1  1; 
       1 1 0 1  0; 
       1 1 1 0  1; 
       1 1 0 0  0; 
       ----------
       1 0 1 1  2; 
       0 1 1 1  0; 
       1 1 0 1  0; 
       1 1 1 0  0; 
       1 1 0 0  1]

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Answer 1

Azzi Abdelmalek 2014-8-8

0
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/146844-how-to-compute-frequency-of-rows-for-submatrices#answer_147905

在 MATLAB Online 中打开

D=[1 0 1 1; 0 1 1 1;1 1 0 1; 1 1 0 1;1 1 0 1; 0 1 1 1; 1 1 1 0; 0 1 1 1; 1 0 1 1; 1 0 1 1; 1 0 1 1; 1 1 0 0]
a=permute(reshape(D',size(D,2),3,[]),[2 1 3]);
uu=unique(D,'rows','stable');
[n,m]=size(uu);
for k=1:size(a,3)
  b=a(:,:,k);
  c=zeros(n,1);
  jj=0;
  for ii=1:n
      jj=jj+1;
      c(jj)=sum(ismember(b,uu(ii,:),'rows'));
  end
  out{k}=[uu c];
end
celldisp(out)

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Answer 2

Azzi Abdelmalek 2014-8-8

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/146844-how-to-compute-frequency-of-rows-for-submatrices#answer_147909

编辑：Azzi Abdelmalek 2014-8-8

在 MATLAB Online 中打开

With one for loop

D=[1 0 1 1; 0 1 1 1;1 1 0 1; 1 1 0 1;1 1 0 1; 0 1 1 1; 1 1 1 0; 0 1 1 1; 1 0 1 1; 1 0 1 1; 1 0 1 1; 1 1 0 0]
uu=unique(D,'rows','stable');
out=[]و
for k=1:3:size(D,1)
  [v1,v2,v3]=unique(D(k:k+2,:),'rows');
  g=[0; histc(v3,1:size(v1,1))];
  [w1,w2]=ismember(uu,v1,'rows');
  c=g(w2+1);
  out{end+1}=[uu c];
end
celldisp(out)