Getting a field in a Class
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I am trying to define a Class. When I create an object of the Class, I want to be able to get one of its properties. I have made it so when I have a 'get' method I can return the property when I use the syntax:
b = newobject(4); % My class only needs to take one int value
val = get(b, 'SomeVal') % this just returns a value
How do I make make my Class so that when I write:
val = b.SomeVal
I get the same result?
Also, this dynamic preview is really slow, is there a way to disable it?
Hmm, having trouble posting the class that I made. It's very poorand I am going to move on and come back to it later
2 个评论
Walter Roberson
2011-8-29
Sorry, there is no way to disable the dynamic preview of the Answers system. The problem is known, and I do not know why it is taking so long to fix.
Daniel Shub
2011-8-31
Can you post some more code about your class. Is your class a subclass of hgsetget? How have you defined get and how have you defined the property SomeVal? What do you currently get when you do b.SomeVal?
回答(1 个)
Lucas García
2011-8-29
You should now be able to do:
b.get('SomeVal')
Or your access method for the SomeVal property has to be defined as public:
properties (GetAccess = public, SetAccess = private)
SomeVal
end
and at some point in the constructor method do:
function obj = newobject(value)
obj.SomeVal(end+1) = value; % end+1 to make it vector based
end
Then you will be able to do:
b.SomeVal
9 个评论
Daniel Shub
2011-9-1
Something is wrong. First, I am pretty sure outp.Value is not a valid property name and that property names cannot have "." in them. Second, you do not need a subsref method to do this. Third, your subsref method is so simple that it is going to cause all sorts of problems as you expand the class. I would suggest posting your entire simplified class file with all the methods.
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