End-of-array value entry

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Maroulator
Maroulator 2014-8-11
评论： Star Strider 2014-8-11
I have the following code which achieves what I need. However, when I tried to make it a bit more sophisticated and perform the substitution I note in the for statement below, I get no results. Cold someone please venture a guess as to why this is the case?
Io=2; K=1.38*(10^(-23)); q=1.602*(10^(-19)); id=-1:0.1:0.6;
for i=1:17 -----> substitute with for i=1:id(end)
T=75;
Vd(i)=((id(i)./Io)+1).*(exp(K*T)/q);
end

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采纳的回答

Star Strider
Star Strider 2014-8-11
Your id array has a maximum of 0.6. In your loop, i=1:0.6 would not execute because the value of the counter at the start, i=1 is already greater than the termination value, 0.6.

更多回答（1 个）

Hikaru
Hikaru 2014-8-11
Instead of substituting with
i=1:id(end)
Use:
i=1:length(id)
You also might want to preallocate Vd since it changes size in every iteration.
  2 个评论
Maroulator
Maroulator 2014-8-11
Hi Hikaru,
Unfortunately this website only allows me to award one "Accept" and it looks like Star Strider was first, so my apologies for not awarding anything to you. Your answer was really helpful all the same and I wanted to note that.
Star Strider
Star Strider 2014-8-11
@Maroulator — You can give him a vote (2 points).

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