End-of-array value entry
5 次查看(过去 30 天)
显示 更早的评论
I have the following code which achieves what I need. However, when I tried to make it a bit more sophisticated and perform the substitution I note in the for statement below, I get no results. Cold someone please venture a guess as to why this is the case?
Io=2; K=1.38*(10^(-23)); q=1.602*(10^(-19)); id=-1:0.1:0.6;
for i=1:17 -----> substitute with for i=1:id(end)
T=75;
Vd(i)=((id(i)./Io)+1).*(exp(K*T)/q);
end
0 个评论
采纳的回答
Star Strider
2014-8-11
Your id array has a maximum of 0.6. In your loop, i=1:0.6 would not execute because the value of the counter at the start, i=1 is already greater than the termination value, 0.6.
0 个评论
更多回答(1 个)
Hikaru
2014-8-11
Instead of substituting with
i=1:id(end)
Use:
i=1:length(id)
You also might want to preallocate Vd since it changes size in every iteration.
2 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!