Recursive binary to decimal function
显示 更早的评论
Hello, I'm trying to write a function that will convert binary to decimal using recursion, but I am having difficulty getting the recursive part.
function y = Bin2dec(BA)
n = length(BA);
if n == 1
y = BA;
else
y = Bin2dec(BA(n-1));
end
1 个评论
Michael Haderlein
2014-8-12
编辑：Michael Haderlein
2014-8-12
I have no idea what kind of conversion you want to do here, but maybe the error is that in case of the recursion (so, the if condition is false), you restart your function not with a limited array but only with one value. Most likely, you need to use
...
else
y = Bin2dec(BA(1:n-1));
end
...
采纳的回答
Geoff Hayes
2014-8-13
Rick - recursion is not really necessary to solve this problem. You can just iterate over each element in the input vector and sum the values according to
function y = myBin2dec(BA)
y = 0;
n = length(BA);
% move left to right in binary sequence
for k=n:-1:1
y = y + BA(n-k+1)*2^(k-1);
end
end
with
myBin2dec([0 0 0 1])
ans =
1
myBin2dec([1 0 0 0])
ans =
8
A recursive version could look like
function y = myBin2dec(BA)
y = 0;
n = length(BA);
if n>0
y = BA(1)*2^(n-1) + myBin2dec(BA(2:end));
end
end
and would return the same results as the previous example.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Numeric Types 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
