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Correct use of uint32

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John
John 2011-8-31
When I do the line
k = idx1* uint32(30e6) + idx2* uint32(0) + idx3* uint32(30e6);
I get an error "Integers can only be combined with integers of the same class, or scalar doubles." However, when I do:
idx1* uint32(30e6);
or
idx1* uint32(30e6) + idx2* uint32(0);
it works. Where am I going wrong? idx is a vector produced by:
idx1 = ( a < b )
where a and b are vectors.
  1 个评论
Oleg Komarov
Oleg Komarov 2011-8-31
I get the error anytime I use idx1*uint32(30e6);
From the code you gave us it should issue the error anytime. Provide more code to understand what's going on.

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采纳的回答

Friedrich
Friedrich 2011-8-31
Hi,
idx1 is a logical vector. So the error can be raised with:
logical(1)*uint32(2)
To get it working, cast idx1 to uint32:
uint32(logical(1))*uint32(2)
ans =
2
So in your case:
k = uint32(idx1)* uint32(30e6) + uint32(idx2)* uint32(0) + uint32(idx3)* uint32(30e6);

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