degrees to radians

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Essence
Essence 2011-9-1
I'm currently trying to find the sin of coordinates which are not in the form of simple degrees i.e it is in the form 123d 43m 15s. How do I write this command in terms of cos and sin? I've tried several commands but I cannot seem to get it right it's saying 'invalid statement'. How do I perform this function?

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采纳的回答

Saneem Ahmed
Saneem Ahmed 2011-9-1
I dont know if there is an inbuilt function. but you can do like this. let 'd' be the degree ,'m' and 's' be the minute and second.Then you can put an equation to convert this format into decimal.
degree=d+(m/60)+(s/3600);
rad=degtorad(degree);
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Saneem Ahmed
Saneem Ahmed 2011-9-1
or try
degree=dmstodegree([d m s]);
rad=degtorad(degree);

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更多回答（1 个）

Andrei Bobrov
Andrei Bobrov 2011-9-1
angleInDegMinSec = [123 43 15]
angleInDegrees = angleInDegMinSec*[1;[1;1/60]/60]
sind(angleInDegrees) % sin
cosd(angleInDegrees) % cos
with Mapping Toolbox
angleInDegMinSec = [123 43 15]
angleInDegees = dms2degrees([123 43 15])
sind(angleInDegrees) % sin
cosd(angleInDegrees) % cos
radians
angleInDegMinSec = [123 43 15]
angleInRadians = angleInDegMinSec*[1;[1;1/60]/60]/180*pi
cos(angleInRadians)
sin(angleInRadians)
or with Mapping Toolbox
angleInRadians = degtorad(dms2degrees(angleInDegMinSec))
cos(angleInRadians)
sin(angleInRadians)

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