Problem with computing inverse using LU
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Hi! I seem to have a problem getting the exact inverse of a matrix using LU. This is the code I made, I already have the code for formulating the L and U, this is just a the inverse part for testing.
l = [ 2 0 0 0
-1 1.5 0 0
0 -1 4/3 0
0 0 -1 1.25];
u = [1 -0.5 0 0
0 1 -2/3 0
0 0 1 -0.75
0 0 0 1];
n = length(a);
x = zeros(n,1);
c = zeros(n,1);
d = zeros(n,1);
inverse = zeros(n);
c(1) = 1;
d(1) = c(1) / l(1,1);
for k=1:n
for i=2:n
sum = 0;
for j=1:i-1
sum = sum + l(i,j) * d(j);
end
d(i) = (c(i) - sum) / l(i,i);
end
x(n) = d(n) / u(n,n);
for i=n-1:-1:1
sum = 0;
for j=i+1:n
sum = sum + u(i,j) * x(j);
end
x(i) = [d(i) - sum] / u(i,i);
end
c(k)=0;
c(k+1)=1;
inverse(:,k) = x;
end
This is the result of my code:
inverse =
0.8 1.4 1.2 1
0.6 1.8 1.4 1
0.4 1.2 1.6 1
0.2 0.6 0.8 1
while the true inverse is
0.8 0.6 0.4 0.2
0.6 1.2 0.8 0.4
0.4 0.8 1.2 0.6
0.2 0.4 0.6 0.8
I tested it and I think that the problem may be in the outermost for loop. I just don't know specifically. Thanks in advance!
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Jutaporn Artniyom
2020-4-27
What is the value of c represent for, and if it's possible to explain how this script work thanks a lot
采纳的回答
Yucheng Ma
2014-8-19
It is my understanding that you would like to implement a C-style matrix inverse procedure using LU decomposition in MATLAB. The code above has a minor mistake in computing the inverse of the L matrix, i.e. "d(1)" is initialized but never updated. I rewrote part of the code and pointed out the difference in the comments. Please refer to the attached file "invLU.m".
In MATLAB, you can use the "inv" function to calculate the inverse of a matrix. You can also use the "mldivide" operator("\") to solve systems of linear equations. The "\" operator is more efficient than explicitly calculating the inverse of a matrix, and can handle singular matrices and sparse matrices.
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