draw two 3D curve but can't hold them in one figure

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Gary
Gary 2014-8-20
评论： Image Analyst 2014-8-20
the first curve is a solution of a differential equation
function dy=eq3(t,y)
dy=zeros(3,1);
dy(1)=-680*(y(1)-100000)/sqrt((y(1)-100000)^2+(y(2)-340*t)^2+(y(3)-10000)^2);
dy(2)=-680*(y(2)-340*t)/sqrt((y(1)-100000)^2+(y(2)-340*t)^2+(y(3)-10000)^2);
dy(3)=-680*(y(3)-10000)/sqrt((y(1)-100000)^2+(y(2)-340*t)^2+(y(3)-10000)^2);
end
and the second one is a line in a 3Dspace
[t,y]=ode45('eq3',[0:0.01:202],[0,0,0]);
plot3(y(:,1),y(:,2),y(:,3))
grid on
hold on
T=0:0.5:200;
X=100000;
Y=340*T;
Z=10000;
plot3(X,Y,Z,'r')
xlabel('x轴')
ylabel('y轴')
zlabel('z轴')
but they don't show up together

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回答（1 个）

Aniruddha Katre
Aniruddha Katre 2014-8-20
The reason why the second plot does not show up is because the variables "X" and "Z" are both scalars while "Y" is a vector. You can just convert "X" and "Z" to vectors of the same dimensions as "Y" and the plot should work. Assuming you want to keep "X" and "Z" constant, you can convert them to vectors in the following manner:
X=100000*ones(length(T),1);
Z=10000*ones(length(T),1);

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