Excluded Digits from vector
显示 更早的评论
vector=[1 2 5 13 55 23 15],excluded dig=5 then out=[1 2 13 23] ,another example vector=[3 24 7 9 18 55 67 71],excluded dig=7 then out=[3 24 9 18 55]
1 个评论
the cyclist
2014-8-22
编辑：the cyclist
2014-8-22
I posted this as a Cody problem . As you may know, Cody rewards brevity of code over all other things.
采纳的回答
the cyclist
2014-8-22
I expect there is a much cleaner method, but here is one that works:
vector = [1 2 5 13 55 23 15];
exDigit = 5;
v = vector;
hasDigit = false(1,numel(v));
while max(v>=1)
hasDigit = hasDigit | mod(v,10)==exDigit;
v = floor(v/10);
end
new_vector = vector(not(hasDigit))
更多回答（2 个）
Guillaume
2014-8-22
str2num(regexprep(num2str(vector), sprintf('\\<\\d*%d\\d*\\>', digit), ''))
Is a neat one liner but may not be faster than the cyclist answer due to the conversion to/from string and the use of regular expression.
4 个评论
Pierre Benoit
2014-8-22
编辑：Pierre Benoit
2014-8-22
Yeah, I used a similar method and found that his method was around 330 times faster.
Guillaume
2014-8-22
Another potential method, faster than regexp but still slower than the cyclist's:
vector(arrayfun(@(n) all(num2str(n)-'0' ~= digit), vector))
the cyclist
2014-8-22
I stole this solution and posted it to Cody. As I write this, it is the leader.
Guillaume
2014-8-22
What? No fair! I should so rightly be the leader! ;)
Ha! Beaten with a variant on my regexp one-line :)
the cyclist
2014-8-22
Here is a solution that came out of Cody. The inputs to the function are the vector v and the excluded digit d.
function ans = digitRemove(v,d)
I = [];
for i = 1 : length(v)
if ~any(ismember( num2str(v(i)) - '0' , d))
I = [I i];
end
end
v(I);
end
类别
在 帮助中心 和 File Exchange 中查找有关 Title 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
