Reduce 3D array by removing NaN elements
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Hi !
I ask you for help in Matlab in order to reduce a 3D array. In column there is three numbers (X,Y,Z coordinates) and each row corresponds to a different point. But these points have to respect a certain condition, otherwise three NaN are stored instead of the coordinates. The third dimension correspond to the time evolution of the coordinates stored in the 2D array.
For exemple:
A(:,:,1) =
1 2 3
NaN NaN NaN
NaN NaN NaN
A(:,:,2) =
NaN NaN NaN
1 2 3
NaN NaN NaN
A(:,:,3) =
NaN NaN NaN
NaN NaN NaN
NaN NaN NaN
If I try:
A(any(any(isnan(A),3),2),:,:) = [];
I get:
Empty array: 0-by-3-by-3
Or I would have:
A(:,:,1) =
1 2 3
NaN NaN NaN
A(:,:,2) =
NaN NaN NaN
1 2 3
A(:,:,3) =
NaN NaN NaN
NaN NaN NaN
The array is reduced but the shape is the same and I don't lose informations.
Thank your for your help and have a nice day !
2 个评论
the cyclist
2014-8-25
What exactly do you want to get rid of? Any row in which all time slices are NaN?
采纳的回答
the cyclist
2014-8-25
编辑:the cyclist
2014-8-25
Maybe you meant all() instead of any()?
idxToRemove = all(all(isnan(A),3),2);
A(idxToRemove,:,:) = []
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