Difference between FFT and DFT spectrum! why ?!
显示 更早的评论
Hi every body, can some one help me to understand the reason of difference between the spectrum of the DFT(raw formulas) and FFT which I have implemented via the following code? I am investigating the harmonics up to 9 KHZ for a signal with 50 hz basic frequency and the differences appear mostly in ranges higher than 6 KHz.
I have run this code on a set of samples with 10004 samples which is attached to this post .(just import the variables to matlab and run the code below )
CODE:
%%reading in the samples
wave; %%%a 10004 samples signal with basic frequency of 50 Hz which means 10 complete period of the fundametal wave
%%Normal FFT
wavefft1 = fft(wave);
L=size(wave,1)-1; % removing the mirror side of spectrum
MagSpec1 = abs(wavefft1(1:1801))/(L/2); %%removing the mirror side of the spectrum
% and ranging the domain
%%DFT implementation
f = 49.985004498650405; %%f = 10/(time(10004)-time(1)) we have used 10 because these samples consist of 10 periods of the signal with 50 Hz frequency
Sampling_Fequency = 50000;
N = size (wave,1)
ll = 0;
for k = 0: f/10:180*f;
cplx_val =0;
for x = 1:N
Teta = ((2*pi*k*x)/Sampling_Fequency);
cplx_val = cplx_val+(wave(x,1)*complex(cos(Teta),(-1*sin(Teta))));
end
ll = ll+1;
MagSpec2(ll,1) = (floor((abs(cplx_val)/(N/2))*10^6))/10^6; %%removing the mirror side of the spectrum
% and ranging the domain
end
%%drawing the caomparison plot
set(0,'DefaultFigureVisible','on');
figure;
x1 = (0:1800)*5;
plot(x1,MagSpec1,'r-');hold on;
plot(x1,MagSpec2,'g-');
legend('FFT Normal','DFT');
2 个评论
Salaheddin Hosseinzadeh
2014-9-1
Ali you can attach your code and sample image here! It's probably easier for lazy ppl like me.
Ali
2014-9-1
采纳的回答
更多回答(0 个)
类别
在 帮助中心 和 File Exchange 中查找有关 Spectral Measurements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!